\(\dfrac{11}{8}:x-\dfrac{2}{5}+-\dfrac{1}{6}=-\dfrac{1}{5}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{5}-\left(-\dfrac{1}{6}\right)\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{5}+\dfrac{1}{6}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{6}{30}+\dfrac{5}{30}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{30}\\ =>\dfrac{11}{8}:x=-\dfrac{1}{30}+\dfrac{2}{5}\\ =>\dfrac{11}{8}:x=-\dfrac{1}{30}+\dfrac{12}{30}\\ =>\dfrac{11}{8}:x=\dfrac{11}{30}\\ =>x=\dfrac{11}{8}:\dfrac{11}{30}\\ =>x=\dfrac{11}{8}.\dfrac{30}{11}\\ =>x=\dfrac{30}{8}\\ =>x=\dfrac{15}{4}\\ \dfrac{4}{7}x-\dfrac{1}{3}x+\left(-\dfrac{16}{21}\right)=-\dfrac{2}{3}\\ =>\left(\dfrac{4}{7}-\dfrac{1}{3}\right)x=-\dfrac{2}{3}-\left(-\dfrac{16}{21}\right)\\ =>\left(\dfrac{12}{21}-\dfrac{7}{21}\right)x=-\dfrac{2}{3}+\dfrac{16}{21}\\ =>\dfrac{5}{21}x=-\dfrac{14}{21}+\dfrac{16}{21}\\ =>\dfrac{5}{21}x=\dfrac{2}{21}\\ =>x=\dfrac{2}{21}:\dfrac{5}{21}\)

\(=>x=\dfrac{2}{21}.\dfrac{21}{5}\\ =>x=\dfrac{2}{5}\\ -\dfrac{11}{12}x+\dfrac{15}{2}\left(x+-\dfrac{1}{5}\right)=\dfrac{67}{8}\\ =>-\dfrac{11}{12}x+\dfrac{15}{2}.x-\dfrac{1}{5}=\dfrac{67}{8}\\ =>\left(-\dfrac{11}{12}+\dfrac{15}{2}\right)x=\dfrac{67}{8}+\dfrac{1}{5}\\ =>\left(-\dfrac{11}{12}+\dfrac{90}{12}\right)x=\dfrac{335}{40}+\dfrac{8}{40}\\ =>\dfrac{79}{12}x=\dfrac{343}{40}\\ =>x=\dfrac{343}{40}:\dfrac{79}{12}\\ =>x=\dfrac{343}{40}.\dfrac{12}{79}\\ =>x=\dfrac{343.12}{40.79}\\ =>x=\dfrac{343.3}{10.79}\\ =>x=\dfrac{1029}{790}\)

a, 1+2+3+4+5+6+7+8+9+...+100

Tổng dãy số trên là :

\(\frac{100.\left(100+1\right)}{2}=5050\)

b, 23+54+32+67+100x0

= 23 + 54 + 32 + 67

= ( 23 + 67 ) + ( 54 + 32 )

= 90 + 86

= 176

Study well 

a, ko ghi đề

=(100+1)+(99+2)+...+(50+51) ( có 50 cặp )

=(101) x 50

=5050

b,ko ghi đề nốt

=(23+54+32+67)+0

=176

Nhớ k đúng mk nha ^^

a) 1 + 2 + 3 + 4 +...+ 100 có: ( 100 - 1 ) : 1 + 1 = 100 ( số hạng )

=> 1 + 2 + 3 + 4 +...+ 100 = ( 100 + 1 ) x 100 : 2 = 5050.

b) 23 + 54 + 32 + 67 + 100 x 0

= 23 + 54 + 32 + 67 

= ( 23 + 67 ) + 54 + 32

= 90 + 54 + 32

= 144 + 32

= 176

Bài 1: 

15 + 65 = 80 

43 + 67 = 110 

65 + 10 = 75 

Bài 2: 

20 < 45 ;  54 < 65 ; 51 < 54 

Bài 3: 

Người về sớm nhất là người về lúc 6 giờ

Bài 1:

15+65=80       43+67=110             65+10=75

Bài 2: 

20<45                   54<65                51<54

Bài 3:

Nhà em.

70

a)-26

b)-142

c)-2

d)0

a) Ta có: (-5)+(-9)+(-12)

=-(5+9+12)

=-26

b) Ta có: (-8)+(-13)+(-54)+(-67)

=(-8-54)+(-13-67)

=-62-80

=-142

c) Ta có: 12+38-30-22

=(12-22)+(38-30)

=-10+8

=-2

d) Ta có: 34+(-43)+66-57

=(34+66)-(43+57)

=100-100

=0

a,[ - 5 ] + [ - 9 ] + [ - 12 ]

= -[ 5 + 9 + 12 ]

= - 26

b, [ - 8] + [-13] + [-54] + [-67]

= [-8] + [-13] + [-52+2] + [-67]

= - { [ 8 + 54] + [13+67]}

= - { 62 + 80 }

= - 142

c, 12 + 38 - 30 - 22

= [12+38]-[30+22]

= 50 - 52

= - 2

d, 34 + [-43]+66-57

= 34 - 43 + 66 - 57

= [ 34 + 66 ] - [ 43 + 57 ]

= 100 - 100

= 0

chúc bạn học tốt

a) 67+135+33

= ( 67+33)+135

= 100 + 135

= 235

b) 146+121+54+379

= ( 146+54)+( 121+379)

= 200 + 500

= 700

c) 198+232-98-32

= ( 232-32)+(198-98)

= 200 + 100

= 300

d)1+2+3+4+.........+50

= ( 50+1) x 50:2 =1275

e)2+4+6+8+..........+100

= ( 100+2) x 50 : 2 =2550

f) 23 x 56 +56

= 1288 + 56

= 1344

g)32 x 19+32

= 608 + 32

= 640

\(a.67+135+33\)

\(=\left(67+33\right)+135\)

\(=100+135=235\)  

\(b.141+121+54+379\)

\(=\left(146+54\right)+\left(121+379\right)\)

\(=200+500=700\)

\(c.198+232-98-32\)

\(=\left(232-32\right)+\left(198-98\right)\)

\(=200+100=300\)

\(f.23.56+56=1288+56=1344\)

\(g.32.19+32=608+32=640\)

bang 197100

bang 197100

bang 197100