\(=\left(x-3\right)\left(8x^3-16x^2\right)=8x^2\left(x-2\right)\left(x-3\right)\)

\(8x^3\left(x-3\right)+16x^2\left(3-x\right)\)

\(=8x^3\left(x-3\right)-16x^2\left(x-3\right)\)

\(=8x^2\left(x-3\right)\left(x-2\right)\)

bạn rút x ra rồi tính ❕

= ( x³ + 2x²y + xy² ) - 16x

= x (x² + 2xy + y²) - 16x

= x( x + y)² - 16x

= x [ ( x + y)² - 16 ]

= x ( x + y +4) ( x + y - 4)

=x.(x²+2xy+y²-16)

=x.[(x+y)²-16]

=x.(x+y-4).(x+y+4)

https://h7.net/hoi-dap/toan-8/phan-h-da-thuc-x-4-16-thanh-nhan-tu-faq324398.html

\(x^4+16x-12\)

\(=x^4+2x^3-2x^2-2x^3-4x^2+4x+6x^2+12x-12\)

\(=x^2.\left(x^2+2x-2\right)-2x.\left(x^2+2x-2\right)+6.\left(x^2+2x-2\right)\)

\(=\left(x^2+2x-2\right)\left(x^2-2x+6\right)\)

Làm

x⁴  + 16x - 12 

= x⁴  + 2x³ - 2x² - 2x³ - 4x² + 4x + 6x ² + 12x - 12

= x² ( x² + 2x - 2 ) - 2x ( x²  + 2x - 2 ) + 6( x²  + 2x - 2 )

=( x²  + 2x - 2 )( x² - 2x + 6 )

_{HỌC TỐT @}

\(A=x^3-15x^4+16x^3-29x^2\)

\(A=\left(x^3+16x^3\right)-15x^4-29x^2\)

\(A=17x^3-15x^4-29x^2\)

\(A=-15x^4+17x^3-29x^2\)

\(A=-x^2\left(15x^2-17x+29\right)\)

\(=-5x^2+15x+x-3=-5x\left(x-3\right)+\left(x-3\right)=\left(1-5x\right)\left(x-3\right)\)

\(16x-5x^2-3=-\left(5x^2-16x+3\right)=-\left[\left(5x^2-15x\right)-\left(x-3\right)\right]=-\left[5x\left(x-3\right)-\left(x-3\right)\right]=-\left(5x-1\right)\left(x-3\right)=\left(5x-1\right)\left(3-x\right)\)