có: nCaCO3= 0,1( mol)
PTPU
C+ O2\(\xrightarrow[]{to}\) CO2
CO2+ C\(\xrightarrow[]{to}\) 2CO
CO2+ Ca(OH)2\(\rightarrow\) CaCO3\(\downarrow\)+ H2O
.0,1.........................0,1................. mol
có: MA= 40( g/ mol)
gọi x là số mol CO có trong A
\(\Rightarrow\) trong A chứa 0,1 mol CO2 và x mol CO
có: 40= \(\frac{44.0,1+28x}{0,1+x}\)
\(\Rightarrow\) x= \(\frac{1}{30}\)
\(\Rightarrow\) \(\sum\)nC= nCO2+ nCO= 0,1+ \(\frac{1}{30}\)= \(\frac{2}{15}\)( mol)
\(\Rightarrow\) nO2= \(\frac{2}{15}\)
\(\Rightarrow\) a= 1,6( g)
V\(\approx\) 2,99( lít)
