\(\frac{2x-1}{2}=\frac{8}{2x-1}\)
\(\Rightarrow\left(2x-1\right)\cdot\left(2x-1\right)=2\cdot8\)
\(\Rightarrow\left(2x-1\right)^2=16\)
\(\Rightarrow\left(2x-1\right)^2=\left(\pm4\right)^2\)
\(\Rightarrow2x-1=4\) hoặc \(2x-1=-4\)
\(2x=4+1\) hoặc \(2x=-4+1\)
\(2x=5\) hoặc \(2x=-3\)
\(x=5:2\) hoặc \(x=-3:2\)
\(x=2,5\) hoặc \(x=-1,5\)
\(\frac{2x-1}{2}=\frac{8}{2x-1}.\)
\(\Rightarrow\left(2x-1\right).\left(2x-1\right)=2.8\)
\(\Rightarrow\left(2x-1\right)^2=16\)
\(\Rightarrow\left(2x-1\right)^2=\left(\pm4\right)^2\)
\(\Rightarrow2x-1=\pm4.\)
\(\Rightarrow\left[{}\begin{matrix}2x-1=4\\2x-1=-4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x=5\\2x=-3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5:2\\x=\left(-3\right):2\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{5}{2}\\x=-\frac{3}{2}\end{matrix}\right.\)
Vậy \(x\in\left\{\frac{5}{2};-\frac{3}{2}\right\}.\)
Chúc bạn học tốt!
\(\frac{2x-1}{2}=\frac{8}{2x-1}\)
\(\Rightarrow\left(2x-1\right)\left(2x-1\right)=2.8\)
\(\Leftrightarrow\left(2x-1\right)^2=16\)
\(\Leftrightarrow\left(2x-1\right)^2=\left(\pm4\right)^2\)
\(\Leftrightarrow2x-1=\pm4\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-1=4\\2x-1=-4\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}2x=4+1\\2x=-4+1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}2x=5\\2x=-3\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\frac{5}{2}\\x=\frac{-3}{2}\end{matrix}\right.\)
Vậy \(x=\frac{5}{2}\)hoặc \(x=\frac{-3}{2}\)
Chúc bạn hok tốt!!! Nguyễn Thanh Trúc. Chúc bạn mai thi tốt nha!!! Nguyễn Thanh Trúc
