ĐK: \(x\ne-\frac{1}{3}\)
\(\frac{4x-3}{3x+1}=\frac{5}{7}\)
\(\Leftrightarrow28x-21=15x+5\)
\(\Leftrightarrow13x=26\)
\(\Leftrightarrow x=2\left(tm\right)\)
S = {2}
\(\frac{4x-3}{3x+1}=\frac{5}{7}\)
\(\Rightarrow\left(4x-3\right).7=\left(3x+1\right).5\)
\(\Rightarrow28x-21=15x+5\)
\(\Rightarrow28x-15x=5+21\)
\(\Rightarrow13x=26\)
\(\Rightarrow x=26:13\)
\(\Rightarrow x=2\)
Vậy \(x=2.\)
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