Ta có \(a+b+c=\sqrt{3}-\left(2+\sqrt{3}\right)+2=0\)
\(\Rightarrow\) Phương trình có hai nghiệm: \(\left\{{}\begin{matrix}x_1=1\\x_2=\frac{2}{\sqrt{3}}=\frac{2\sqrt{3}}{3}\end{matrix}\right.\)
bài 1:giải PT
a.\(\dfrac{x2}{\sqrt{5}}-\sqrt{20}=0\)
b.\(\sqrt{\left(x-3\right)^2}-9=0\)
c.\(\sqrt{4x^2+4x+1}=6\)
Cho x,y,z >0 t/m x2+y2+z2=3.
C/m \(\dfrac{x}{\sqrt[3]{yz}}+\dfrac{y}{\sqrt[3]{xz}}+\dfrac{z}{\sqrt[3]{xy}}\ge xy+yz+zx\)
cho phương trình ẩn x: \(x-\sqrt{6x}-3+2m=0\left(1\right)\)
tìm m để pt có 2 nghiệm x = x1, x = x2 thỏa mãn \(\frac{x_1+x_2}{\sqrt{x_1}+\sqrt{x_2}}=\frac{\sqrt{24}}{3}\)
Giải các pt sau :
a) \(\sqrt{x+5}+\sqrt{x+2}+2x-1=0\)
b) \(\sqrt{5x^3-1}+\sqrt[3]{2x-2}+x-4=0\)
c) \(\sqrt[3]{x^2-1}+x=\sqrt{x^3-2}\)
d) \(\sqrt[3]{x^2}-2\sqrt[3]{x}-\left(x-4\right)\sqrt{x-7}-3x+28=0\)
gpt : a) \(\frac{2+\sqrt{x}}{\sqrt{2}+\sqrt{2+\sqrt{x}}}+\frac{2-\sqrt{x}}{\sqrt{2}-\sqrt{2-\sqrt{x}}}=\sqrt{2}\)
b) \(\sqrt[3]{x+1}+\sqrt[3]{x+2}+\sqrt[3]{x+3}=0\)
c) \(\sqrt[4]{1-x^2}+\sqrt[4]{1+x}+\sqrt[4]{1-x}=3\)
Giải các pt sau:
a) \(\sqrt{x+8}+\frac{9x}{\sqrt{x+8}}-6\sqrt{x}=0\)
b) \(x^4-2x^3+\sqrt{2x^3+x^2+2}-2=0\)
c) \(3x\sqrt[3]{x+7}\left(x+\sqrt[3]{x+7}\right)=7x^3+12x^2+5x-6\)
d) \(4x^2+\left(8x-4\right)\sqrt{x}-1=3x+2\sqrt{2x^2+5x-3}\)
e) \(16x^2+19x+7+4\sqrt{-3x^2+5x+2}=\left(8x+2\right)\left(\sqrt{2-x}+2\sqrt{3x+1}\right)\)
f) \(\left(5x+8\right)\sqrt{2x-1}+7x\sqrt{x+3}=9x+8-\left(x+26\right)\sqrt{x-1}\)
g) \(\sqrt[3]{3x+1}+\sqrt[3]{5-x}+\sqrt[3]{2x-9}-\sqrt[3]{4x-3}=0\)
a,\(\sqrt{a^3}-\sqrt{b^3}+\sqrt{a^2.b}-\sqrt{a.b^2}\left(Vớia>0,b>0\right)\)
b,\(x-y+\sqrt{x.y^2}-\sqrt{y^3}\left(Vớix>0,y>0\right)\)
Giải phương trình:
1, \(\sqrt{x-2}+\sqrt{4-x}=2x^2-5x-3\)
2, \(\sqrt[3]{x^2-1}+x=\sqrt{x^3-2}\)
3, \(\sqrt[3]{x^2}-2\sqrt[3]{x}-\left(x-4\right)\sqrt{x-7}-3x+28=0\)
Giai phuong trinh
a/ \(\sqrt{4x^2+4x+1}\) - \(\sqrt{25x^2+10x+1}\) = 0
b/ \(\sqrt{x^4-16x^2+64}=\sqrt{25x^2+10x+1}\)
c/ \(\sqrt{x^2-25}-\sqrt{x-5}=0\)
d/ \(\sqrt{4x^2-9}-2\sqrt{2x+3}=0\)
e/ \(\sqrt{x-2}-3\sqrt{x^2-4}=0\)
Rút gọn các biểu thức sau:
a) \(\dfrac{4}{\sqrt{11}-3}-\dfrac{5}{4+\sqrt{11}}\)
b) \(\left(\dfrac{3\sqrt{x}}{x-2\sqrt{x}}-\dfrac{2}{\sqrt{x}+3}\right):\dfrac{\sqrt{x}+13}{x+6\sqrt{x}+9}\) với x>0;x\(\ne\)4
