Question

So sánh:

\(S=\dfrac{1}{\sqrt{1\cdot2012}}+\dfrac{1}{\sqrt{2\cdot2011}}+...+\dfrac{1}{k\sqrt{2012-k+1}}+...+\dfrac{1}{\sqrt{2012\cdot1}}\text{ }và\text{ }\dfrac{4024}{2013}\)

Answer 1

\(S=\dfrac{1}{\sqrt{1.2012}}+\dfrac{1}{\sqrt{2.2011}}+...+\dfrac{1}{\sqrt{2012.1}}>\dfrac{1}{\dfrac{1+2012}{2}}+\dfrac{1}{\dfrac{2+2011}{2}}+...+\dfrac{1}{\dfrac{2012+1}{2}}=\dfrac{2012}{\dfrac{2013}{2}}=\dfrac{4024}{2013}\)