Chương I : Số hữu tỉ. Số thực

bài 2:tìm x giá trị biểu thức

a)2-\(|^{ }_{ }\)3x-\(\frac{1}{4}|\)=\(\left|-\frac{5}{4}\right|\) f)-2,5:\(\left|\frac{3}{4}x+\frac{1}{2}\right|=3\) b)5-3.\(\left|5-2x\right|\)=-4,5 g)\(\left|2x-5\right|=\left|x=1\right|\)

c)\(\frac{3}{2}+\frac{3}{4}.\left|x-\frac{3}{4}\right|=\frac{7}{4}\)

d)\(\frac{11}{4}+\frac{3}{2}\left|4x-\frac{1}{5}\right|=\frac{7}{2}\)

e)\(\frac{21}{5}+3:\left|\frac{x}{4}-\frac{2}{3}\right|=6\) h)\(\left|\right|2x+1|-3|=\left|-5\right|\)

a)\(\frac{-3}{2}-2x+\frac{3}{4}=-2\) b)\(\left(\frac{-2}{3}x-\frac{3}{5}\right)\left(\frac{3}{-2}-\frac{10}{3}\right)=\frac{2}{5}\) c)\(\frac{x}{2}-\left(\frac{3x}{5}-\frac{13}{5}\right)=-\left(\frac{7}{5}+\frac{7}{10}.x\right)\) d)\(\frac{2x-3}{3}+\frac{-3}{2}=\frac{5-3x}{6}-\frac{1}{3}\) e)\(\frac{2}{3x}-\frac{3}{12}=\frac{4}{5}-\left(\frac{7}{x}2\right)\) k)\(\frac{13}{x-1}+\frac{5}{2x-2}-\frac{6}{3x-3}\) m)\(\left(\frac{3}{2}-\frac{2}{-5}\right):x-\frac{1}{2}=\frac{3}{2}\) n)\(\left(\frac{3}{2}-\frac{5}{11}-\frac{3}{13}\right)\left(2x-2\right)=\left(\frac{-3}{4}+\frac{5}{22}+\frac{3}{26}\right)\) Giải giúp mk mk đang cần ghấp trong hôm nay cám ơn mọi người

\(\frac{1}{4}\)+\(\frac{3}{4}\):2x = -5

Bài 1:Tính

\(\frac{\frac{1}{3}-\frac{4}{5}}{\frac{1}{3}+\frac{4}{5}}.\frac{\frac{3}{4}-\frac{5}{3}}{\frac{3}{4}+\frac{5}{3}}:\frac{\frac{4}{5}-1}{1-\frac{2}{3}}\)