\(2\sqrt{18x}-\sqrt{27x}=12\) \(\left(x\ge0\right)\)
\(\Leftrightarrow6\sqrt{2x}-3\sqrt{3x}-12=0\)
\(\Leftrightarrow\sqrt{x}\left(6\sqrt{2}-3\sqrt{3}\right)=12\)
\(\Leftrightarrow\sqrt{x}=\frac{12}{6\sqrt{2}-3\sqrt{3}}\) \(\Leftrightarrow x=\frac{176+64\sqrt{6}}{25}\)
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