Bài 8: Rút gọn biểu thức chứa căn bậc hai
Các câu hỏi tương tự
Câu 1A(dfrac{1}{1-sqrt{x}}+dfrac{x+2}{xsqrt{x}-1}+dfrac{sqrt{x}}{x+sqrt{x}+1}):dfrac{sqrt{x}-1}{5}Câu2A(dfrac{xsqrt{x}-1}{x-sqrt{x}}-dfrac{xsqrt{x}+1}{x+sqrt{x}}):dfrac{2left(x-2sqrt{x}+1right)}{x-1} (vơi x0,x≠1)câu3L(dfrac{sqrt{a}-2}{a-1}-dfrac{sqrt{a}+2}{a+2sqrt{a}+1}).(1+dfrac{1}{sqrt{a}}) (với a0,a≠1)mong các cao nhân giải giúp✿giải các bước chi tiết ạcảm ơn mọi người nhiều
Đọc tiếp
Câu 1
A=(\(\dfrac{1}{1-\sqrt{x}}\)+\(\dfrac{x+2}{x\sqrt{x}-1}\)+\(\dfrac{\sqrt{x}}{x+\sqrt{x}+1}\)):\(\dfrac{\sqrt{x}-1}{5}\)
Câu2
A=(\(\dfrac{x\sqrt{x}-1}{x-\sqrt{x}}\)-\(\dfrac{x\sqrt{x}+1}{x+\sqrt{x}}\)):\(\dfrac{2\left(x-2\sqrt{x}+1\right)}{x-1}\) (vơi x>0,x≠1)
câu3
L=(\(\dfrac{\sqrt{a}-2}{a-1}\)-\(\dfrac{\sqrt{a}+2}{a+2\sqrt{a}+1}\)).(1+\(\dfrac{1}{\sqrt{a}}\)) (với a>0,a≠1)
mong các cao nhân giải giúp✿
giải các bước chi tiết ạ
cảm ơn mọi người nhiều
(\(1+\dfrac{\sqrt{x}}{\sqrt{x}+1}\)) : (\(\dfrac{1}{\sqrt{x}-1}-\dfrac{2\sqrt{x}}{x\sqrt{x}+\sqrt{x}-x-1}\)) - \(\dfrac{x\sqrt{x}+1}{x-\sqrt{x}+1}\)
\(\dfrac{x\sqrt{x}-1}{x-\sqrt{x}}-\dfrac{x\sqrt{x}+1}{x+\sqrt{x}}+\left(\sqrt{x}-\dfrac{1}{\sqrt{x}}\right)\times\left(\dfrac{\sqrt{x}+1}{\sqrt{x}-1}+\dfrac{\sqrt{x}-1}{\sqrt{x}+1}\right)\)
rút gọn biểu thức và tìm a để N=7
\(B=\dfrac{2\sqrt{x}}{\sqrt{x}+3}+\dfrac{x+9\sqrt{x}}{9-x};\left(x\ge0;x\ne9;x\ne16\right)\)
\(B=\dfrac{3}{\sqrt{x}-3}+\dfrac{2}{\sqrt{x}+3}+\dfrac{x-5\sqrt{x}-3}{x-9}\)
\(B=\dfrac{\sqrt{x}+1}{\sqrt{x}-1}-\dfrac{x+\sqrt{x}}{x-1};\left(x>0;x\ne1\right)\)
Adfrac{sqrt{x}+2}{sqrt{x}-2}-dfrac{3}{sqrt{x}+2}+dfrac{12}{x-4}Bdfrac{sqrt{x}}{sqrt{x}-3}-dfrac{sqrt{x}-21}{9-x}dfrac{1}{sqrt{x}+3}Cdfrac{sqrt{x}}{sqrt{x}+3}+dfrac{2sqrt{x}}{sqrt{x}-3}-dfrac{3x+9}{x-9}Ddfrac{1}{sqrt{x}+3}-dfrac{sqrt{x}}{3-sqrt{x}}+dfrac{2sqrt{x}+12}{x-9}Ndfrac{sqrt{x}}{sqrt{x}-1}+dfrac{2sqrt{x}-1}{sqrt{x}+1}-dfrac{6}{x-1}Mdfrac{3}{sqrt{x}-3}+dfrac{2}{sqrt{x}+3}+dfrac{x-5sqrt{x}-3}{x-9}
Đọc tiếp
\(A=\dfrac{\sqrt{x}+2}{\sqrt{x}-2}-\dfrac{3}{\sqrt{x}+2}+\dfrac{12}{x-4}\)
\(B=\dfrac{\sqrt{x}}{\sqrt{x}-3}-\dfrac{\sqrt{x}-21}{9-x}\dfrac{1}{\sqrt{x}+3}\)
\(C=\dfrac{\sqrt{x}}{\sqrt{x}+3}+\dfrac{2\sqrt{x}}{\sqrt{x}-3}-\dfrac{3x+9}{x-9}\)
\(D=\dfrac{1}{\sqrt{x}+3}-\dfrac{\sqrt{x}}{3-\sqrt{x}}+\dfrac{2\sqrt{x}+12}{x-9}\)
\(N=\dfrac{\sqrt{x}}{\sqrt{x}-1}+\dfrac{2\sqrt{x}-1}{\sqrt{x}+1}-\dfrac{6}{x-1}\)
\(M=\dfrac{3}{\sqrt{x}-3}+\dfrac{2}{\sqrt{x}+3}+\dfrac{x-5\sqrt{x}-3}{x-9}\)
Rút gọn
A=\(\frac{x+2}{x\sqrt{x}-1}+\frac{\sqrt{x}+1}{x+\sqrt{x}+1}+\frac{1}{1-\sqrt{x}}\)
B=\(\left(\frac{\sqrt{x}+1}{\sqrt{x}-1}-\frac{\sqrt{x}-1}{\sqrt{x}+1}+4\sqrt{x}\right).\left(\sqrt{x}+\frac{1}{\sqrt{x}}\right)\)
C=\(\left(\frac{1}{\sqrt{x}+1}-\frac{2\sqrt{x}-2}{x\sqrt{x}-\sqrt{x}+x-1}\right):\left(\frac{1}{\sqrt{x}-1}-\frac{2}{x-1}\right)\)
Rút gọn:
A=\(\left(\dfrac{x-\sqrt{x}+2}{x-\sqrt{x}-2}-\dfrac{x}{x-2\sqrt{x}}\right)\div\dfrac{1-\sqrt{x}}{2-\sqrt{x}}vớix>0,x\ne1\)
B=\(\left(\dfrac{x}{3+\sqrt{x}}+\dfrac{1}{\sqrt{x}+3}\right)\div\left(1-\dfrac{2}{\sqrt{x}}+\dfrac{6}{x+3\sqrt{x}}\right)\)
Lm nhanh giúp mk nhé!
45. CIOOA = ((sqrt(x) - 4)/(sqrt(x) * (sqrt(x) - 2)) + 3/(sqrt(x) - 2)) / ((sqrt(x) + 2)/(sqrt(x)) - (sqrt(x))/(sqrt(x) - 2)) a) Rút gọn A VỚI x > 0 , x ne4 b ) Tỉnh A với x = 6 - 2sqrt(5)
Rút gọn
A=\(\left(\dfrac{\sqrt{x}}{3+\sqrt{x}}+\dfrac{2x}{9-x}\right)\div\left(\dfrac{\sqrt{x}+1}{x-3\sqrt{x}}-\dfrac{2}{\sqrt{x}}\right)\)
B=\(\left(\dfrac{1}{x+\sqrt{x}}-\dfrac{1}{\sqrt{x}+1}\right)\div\dfrac{\sqrt{x}-1}{x+2\sqrt{x}+1}+1\)
1. cho biểu thức
A=\(\left(\dfrac{x\sqrt{x}-1}{x-\sqrt{x}}-\dfrac{x\sqrt{x}+1}{x+\sqrt{x}}\right)\left(\dfrac{\sqrt{x}}{\sqrt{x}-1}-\dfrac{1}{\sqrt{x}+1}\right)\)
a. rút gọn