Question

X²⁰¹⁸=X²⁰¹⁹.hãy tìm số tự nhiên X

Answer 1

x = 0;1

Answer 2

\(x^{2018}=x^{2019}\Leftrightarrow x^{2019}-x^{2018}=0\Leftrightarrow x^{2018}\left(x-1\right)=0\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)

Vậy...

Answer 3

Có: \(x^{2018}=x^{2019}\\ \Leftrightarrow x^{2018}-x^{2019}=0\\ \Leftrightarrow x^{2018}\left(1-x\right)=0\\ \Rightarrow\left[{}\begin{matrix}x^{2018}=0\\1-x=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=1-0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)

Vậy \(x\in\left\{0;1\right\}\)

Answer 4

x= 1 hoặc 0 nhé