\(\dfrac{x+1}{x+4}-\dfrac{x^2-4}{x^2-16}\\ =\dfrac{x+1}{x+4}-\dfrac{x^2-4}{\left(x-4\right)\left(x+4\right)}\\ =\dfrac{\left(x+1\right)\left(x-4\right)-x^2+4}{\left(x+4\right)\left(x-4\right)}\\ =\dfrac{x^2+x-4x-4-x^2+4}{\left(x+4\right)\left(x-4\right)}\\ =\dfrac{-3x}{\left(x+4\right)\left(x-4\right)}\)