x2+1=17
x2 =16
x2 =42
\(\Rightarrow\)x=4
\(x^2-1=17\)
\(\Rightarrow x^2=18\)
\(\Rightarrow x\in\left\{\varnothing\right\}\)
Vậy \(x\in\left\{\varnothing\right\}\)
\(x^2-1=17\)
\(x^2=17+1\)
\(x^2=18\)
\(x=\sqrt{18}\)
\(x^2-1=17\)
\(x^2=17+1\)
\(x^2=18\)
\(x=\sqrt{18}\)
x2- 1 = 17
→x2 - 12 = 17
→x - 1 = 17
x = 17 + 1
x = 18
Sai đề.
Sửa:
\(x^2+1=17\)
\(x^2=17-1\)
\(x^2=16\)
Ta thấy: 16 = 42
\(\rightarrow x^2=4^2\)
\(\rightarrow x=4\)