Question

x + \(\dfrac{30}{100}\).x=-1,31

Answer 1

\(x+\dfrac{30}{100}.x=-1,31\\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ x.\left(1+\dfrac{30}{100}\right)=\dfrac{-131}{100}\\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ x.\left(\dfrac{100}{100}+\dfrac{30}{100}\right)=\dfrac{-131}{100}\\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ x.\dfrac{26}{20}=\dfrac{-131}{100}\\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\\\ \\ x=\dfrac{-131}{100}:\dfrac{26}{20}=\dfrac{-131}{100}.\dfrac{20}{26}\\ \\ \\ \\ \\ \\ \\ \\ \\\\ \\ x=\dfrac{-131}{130}\)

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Answer 2

x+\(\dfrac{30}{100}\).x=-1,31

x+0,3.x=-1,31

x.(0,3+1)=-1,31

x.1,3=-1,31

x=-1,31:1,3

x=\(\dfrac{-131}{130}\)

Vậy x=\(\dfrac{-131}{130}\)

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Answer 3

x+\(\dfrac{30}{100}\).x=-1,31

x.1+\(\dfrac{30}{100}\)x=\(\dfrac{-131}{100}\)

x(1+\(\dfrac{30}{100}\))=\(\dfrac{-131}{100}\)

x(\(\dfrac{100}{100}\)+\(\dfrac{30}{100}\))=\(\dfrac{-131}{100}\)

x.\(\dfrac{130}{100}\)=​​​\(\dfrac{-131}{100}\)​

x=\(\dfrac{-131}{100}\):\(\dfrac{130}{100}\)

x=\(\dfrac{130}{100}\).\(\dfrac{100}{131}\)

x=\(\dfrac{100.130}{131.100}\)

x=\(\dfrac{130.1}{131.1}\)

x=\(\dfrac{130}{131}\)