Question

Tinh x,biet AB//CD

Answer 1

Qua F kẻ tia Ft nằm trong góc EFH và Ft// AB

Ta có : Bt // AB

⇒ \(\widehat{BEF}=\widehat{EFt}\) ( 2 góc so le trong )

Mà \(\widehat{BEF}=20^0\Rightarrow\widehat{EFt}=20^o\)

Vậy \(\widehat{EFt}=20^o\)

Ta có : \(\widehat{EFt}+\widehat{tFH}=\widehat{EFH}\)

\(20^o+\widehat{tFH}=95^o\)

\(\widehat{tFH}=95^0-20^0\)

\(\widehat{tFH}=75^0\)

Vậy \(\widehat{tFH}=75^0\)

Ta có :

Ft // AB

AB// CD

⇒ Ft//CD

Ta có : Ft // CD ( CMT )

⇒ \(\widehat{tFH}=\widehat{FHD}\) ( 2 góc so le trong )

\(Mà\) \(\widehat{tFH}=75^0\Rightarrow\widehat{FHD}=75^0\)

Vậy \(\widehat{FHD}=75^0\) hay \(x=75^0\)

Answer 2

TINH X BIET AB//CD NHA CAC BAN MK DANG CAN GAP GIUP MK VOI

Answer 3

X=75