Question

(x - 5)² = (1 - 3x)²

Có 2 TH

Answer 1

\(\left(x-5\right)^2=\left(1-3x\right)^2\)

\(\left(x-5\right)^2:\left(1-3x\right)^2=0\)

\(\left(\frac{x-5}{1-3x}\right)^2=0\)

\(\Rightarrow\frac{x-5}{1-3x}=0\)

\(\Rightarrow x-5=0\)

\(\Rightarrow x=5\)

Answer 2

( x- 5)² = (1-3x)² 

(x - 5 )² : ( 1 - 3x )² = 0 

(\(\frac{x-5}{1-3x}\)) ² = 0

=>\(\frac{x-5}{1-3x}\) = 0 => x - 5 =0

     => x = 5