\(\left(x-3\right)^2=\left(x-3\right)^5\\ \dfrac{\left(x-3\right)^2}{\left(x-3\right)^2}=\dfrac{\left(x-3\right)^5}{\left(x-3\right)^2}\\ 1=\left(x-3\right)^3\\ \Rightarrow x-3=1\Rightarrow x=4\)
(x - 3)2 = (x - 3)5
\(\Rightarrow\) x - 3 = 0 hoặc 1
\(\Rightarrow\) x = 3 hoặc 4