Question

x-3/2014+x-2/2015=X-2015/2=x-2014/3 giúp mình giải với

Answer 1

\(\dfrac{x-3}{2014}+\dfrac{x-2}{2015}=\dfrac{x-2015}{2}+\dfrac{x-2014}{3}\)

⇔ \(\dfrac{x-3}{2014}-1+\dfrac{x-2}{2015}-1=\dfrac{x-2015}{2}-1+\dfrac{x-2014}{3}-1\)

⇔ \(\dfrac{x-2017}{2014}+\dfrac{x-2017}{2015}=\dfrac{x-2017}{2}+\dfrac{x-2017}{3}\)

⇔ \(\left(x-2017\right)\)\(\left(\dfrac{1}{2014}+\dfrac{1}{2015}-\dfrac{1}{2}-\dfrac{1}{3}\right)=0\)

Do : \(\dfrac{1}{2014}< \dfrac{1}{2015}< \dfrac{1}{2}< \dfrac{1}{3}\)

⇒ \(\dfrac{1}{2014}+\dfrac{1}{2015}-\dfrac{1}{2}-\dfrac{1}{3}< 0\)

⇔ x - 2017 = 0

⇔ x = 2017

KL....