\(\left(x-2\right)\left(5-x\right)>0\)
\(\Rightarrow\left\{{}\begin{matrix}x-2>0\\5-x>0\end{matrix}\right.\) hoặc \(\left\{{}\begin{matrix}x-2< 0\\5-x< 0\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x>2\\x< 5\end{matrix}\right.\)\(\Rightarrow2< x< 5\) hoặc \(\left\{{}\begin{matrix}x< 2\\x>5\end{matrix}\right.\) (vô lí)
Vậy 2 < x < 5
tìm x thuộc Z
1/ x.(x+7)=0
2/ (x+12). (x-3)=0
3/ (-x +5).(3-x)=0
4/x.(2+x).(7-x)=0
5/(x-1).(x+2).(-x-3)=0
-5x- 16 = 40 + x
4x - 10 = 15 - x
- 12 ( x - 5 ) + 7 ( 3 - x ) = 5
( x - 2 ) . ( x + 15 ) = 0
( x - 2 ) . ( x2 - 1 ) = 0
( 7 - x ). | x + 19 | = 0
( x - 3 ) . ( x - 5 ) < 0
(Giúp mifh với )
13) -12( x - 5 ) + 7( 3 - x ) = 5
14) ( x - 2 ) . ( x + 4 ) = 0
15) ( x - 2 ) . ( x + 15 ) = 0
16) ( 7 - x ) . ( x + 19 ) = 0
17 ) -5 < x < 1
18) \(\left|x\right|\) < 3
19) ( x - 3 ) ( x - 5 ) < 0
20) 2x2 - 3 = 29
Tìm x
1) -12(x-5)+7(3-x)=5
2) (x-2)*(x+4)=0
3) (x-2)*(x+15)=0
4) (7-x)*(x+19)=0
5) (x-3)*(x-5)<0
Tìm x thuộc Z:
1.x2 -5x=0
2.|x-9|.(-8)=-16
3.|4-5x|=24 với x< hoặc= 0
4.x.(x-2)>0
5.x.(x-2)<0
6. (x-1).(y+1)=5
7.x(y+2)=-8
8.xy-2x-2y=0
9.2x-5 chia hết cho x-1
tìm x€Z :
a) -12 (x -5)+7 (3- x) = 5
b) (x - 2)(x + 4) = 0
c) (x - 2)(x + 15) = 0
d) (7-x)(x + 19) = 0
Tìm x
A) (x+2) . (x+5) <0
B) (x+2) . (x+5) >0
giúp mk nhé
Bai 1 :Cho M=-3.(5+17)+5.(3-17)
N=(-15+1).(-15+2)...(-15+100)
So sánh M và N
Bài 2
P1=(-3).7.(-2).(-13)
P2=(-1).(-2).(-3).(-4).5
So sanh P2 với P1 mà không thực hiện phép tính.
Bài 3:tìm x thuộc Z
a)x.(x-1)=0
b)(x-3).(x+4)=0
c)(2x-4).(x+2)=0
d)(x+1)^2.(x-2)^2=0
e) x(x+1).(x+2)^2.(x+3)^3=0
f)(x-9)^5.(x-5)^8=0
g)x(x+100)^10.(x+2000)^20.(x+300)^300=0
h)(x-2)^2=0
tìm xϵz , biết :
a) (x - 2 ) . ( x + 4 ) = 0
b) (x - 2 ) . ( x + 15 ) = 0
c ) ( 7 - x ) . ( x + 19 ) = 0
d) -5 < x < 1
e) |x| < 3
g ) ( x - 3 ) . ( x - 5 ) < 0
a) (x - 2 ) . ( x + 4 ) = 0
b) (x - 2 ) . ( x + 15 ) = 0
c) ( x - 3 ) . ( x - 5 ) < 0
