\(\dfrac{\left(x-2\right)}{\left(x-1\right)}=\dfrac{\left(x+4\right)}{\left(x+7\right)}\)
\(\Rightarrow\left(x-2\right)\left(x+7\right)=\left(x+4\right)\left(x-1\right)\)
\(\Rightarrow x^2+7x-2x-14=x^2-x+4x-4\)
\(\Rightarrow x^2+5x-14=x^2+3x-4\)
\(\Rightarrow x^2+5x-x^2-3x=-4+14\)
\(\Rightarrow2x=10\Rightarrow x=\dfrac{10}{2}=5\)
Vậy......