\(\left(x-2\right)^3=0\)
\(\Leftrightarrow x-2=0\)
\(\Leftrightarrow x=2\)
Đúng 2
Bình luận (0)
Bài 4: Phương trình tích
Các câu hỏi tương tự
1. x^4+x^2-2=0; 2. x^3+3x^2+6x+4=0; 3. x^3-6x^2+8x=0; 4. x^4-8x^3-9x^2=0 Giúp với (;~;)
a) ( x+5)(2x-3)=0
b) ( x^2+1)(6x+3)=0
C) 2(x+3)(x-4)=0
Xem chi tiết
1.4x2-12x+5=0
2.2x2+5x+3=0
3.x2+x-2=0
4.x2-4x+3=0
5.2x2+5x-3=0
6.x2+6x-16=0
a,x^2-9x+20=0
b,x^3-4x^2+5x=0
c,x^2=2x-15=0
d,(x^2-1)^2=4x+1
e,4x^3-9x^2+6x-1=0
f,x^4-4x^3-x^2+16x-12=0
Giải phương trình:
a, (x+2)(x-3)=0
b, (x-5)(7-x)=0
c, (2x+3)(-x+7)=0
d, (-10x+5)(2x-8)=0
e, (x-1)(x+5)(-3x+8)=0
f, (x-1)(3x+1)=0
g, (x-1)(x+2)(x-3)=0
h, (5x+3)(x2+4)(x-1)=0
a) (2x +1)(3 – x)(4 - 2x) = 0 b)2x(x – 3) + 5(x – 3) = 0
c) (x2 – 4) – (x – 2)(3 – 2x) = 0 d) x2 – 5x + 6 = 0
e) (2x + 5)2 = (x + 2)2 f) 2x3 + 6x2 = x2 + 3x
1,Giải PT sau
a, (5x+3)(x2+4)(x-4)=0
b, (4x-1)(x-3)-(x-2)(5x+2)=0
c, (x+3)(x-5)+(x+3)(3x-4)=0
d, (x+6)(3x-1)+x2-36=0
e, 0,75x(x+5)=(x+5)(3-1,25x)
1) x3-x2-2=0
2) 4x2-12x+5=0
3) x4+6x2+8=0
4) x3-x2-21x+45=0
Giải PT:
(3x)^2-4(x-3)^2=0
x^3+x^2+4=0
(x-1)^2.(x-3)+(1-x)^2.(x+3)=72
10x+3/12=1+6:8x/9
2x+7x5 5x+1=0
2x(x-5)-x+5=0
(x+3)^2-(5-x)(x+3)=0
(x+2)(3-4x)=x^2+4x+4