\(\left(x+\dfrac{1}{2}\right)\)\(\left(\dfrac{2}{3}-2x\right)\)= 0 \(\Rightarrow\) \(\left[{}\begin{matrix}\left(x+\dfrac{1}{2}\right)=0\\\left(\dfrac{2}{3}-2x\right)=0\end{matrix}\right.\) \(\Rightarrow\)\(\left[{}\begin{matrix}x=\dfrac{-1}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)