Question

 ( x + 1 phần 2 ) * ( 2 phần 3 - 2x ) = 0

mọi ng giải càng nhanh càng tốt nhé

Answer 1

Ta có: \(\left(x+\frac{1}{2}\right)\left(\frac{2}{3}-2x\right)=0\)

\(\Leftrightarrow\) \(\left[\begin{array}{nghiempt}x+\frac{1}{2}=0\\\frac{2}{3}-2x=0\end{array}\right.\) \(\Leftrightarrow\) \(\left[\begin{array}{nghiempt}x=-\frac{1}{2}\\2x=\frac{2}{3}\end{array}\right.\) \(\Leftrightarrow\) \(\left[\begin{array}{nghiempt}x=-\frac{1}{2}\\x=\frac{1}{3}\end{array}\right.\)

 

Answer 2

\(\left(x+\frac{1}{2}\right)\times\left(\frac{2}{3}-2x\right)=0\)

\(\Rightarrow x+\frac{1}{2}=0\)

     \(x=0-\frac{1}{2}\)

     \(x=-\frac{1}{2}\)

\(\Rightarrow\left(\frac{2}{3}-2x\right)=0\)

        \(2x=\frac{2}{3}-0\)

        \(2x=\frac{2}{3}\)

           \(x=\frac{2}{3}\div2\)

            \(x=\frac{1}{3}\)

Vạy tồn tại hai giá trị \(-\frac{1}{2}\) và \(\frac{1}{3}\)