a, \(\dfrac{5}{6}=\dfrac{1}{2}+\dfrac{1}{3}\)
b, \(\dfrac{7}{8}=\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}\)
c, \(\dfrac{6}{5}=\dfrac{1}{1}+\dfrac{1}{5}\)
d, \(\dfrac{8}{7}=\dfrac{1}{1}+\dfrac{1}{7}\)
\(a,\dfrac{5}{6}=\dfrac{1}{2}+\dfrac{1}{3}\\ b,\dfrac{7}{8}=\dfrac{1}{8}+\dfrac{1}{4}+\dfrac{1}{2}\\ c,\dfrac{6}{5}=\dfrac{1}{1}+\dfrac{1}{5}\\ d,\dfrac{8}{7}=\dfrac{1}{1}+\dfrac{1}{7}\)
Giải:
a) \(\dfrac{5}{6}=\dfrac{1}{2}+\dfrac{1}{3}\)
b) \(\dfrac{7}{8}=\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}\)
c) \(\dfrac{6}{5}=\dfrac{1}{1}+\dfrac{1}{5}\)
d) \(\dfrac{8}{7}=\dfrac{1}{1}+\dfrac{1}{7}\)
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