\(x^3y^3+125=\left(xy+5\right)\left(x^2y^2-5xy+25\right)\)
Đúng 0
Bình luận (0)
\(x^3y^3+125=\left(xy+5\right)\left(x^2y^2-5xy+25\right)\)
viet cac bieu thuc sau duoi dang tich;
a,x\(^3\)y\(^3\)+225
viet cac bieu thuc sau duoi dang tich:
a, -64+(x-3)\(^3\)
viet cac bieu thuc sau duoi dang tich:
a, -64+(x-3)\(^3\)
viet cac bieu thuc sau duoi dang tich:
b,(a-1)\(^3\)-(a+1)\(^3\)
viet cac bieu thuc sau duoi dang tich:
b,(a-1)\(^3\)-(a+1)\(^3\)
viet cac bieu thuc sau duoi dang tich:
a, a\(^6\)-b\(^6\)
viet cac bieu thuc sau duoi dang tong:
a,(4-xy)^3
b,(0,1+xy)^3
viet cac bieu thuc sau duoi dang tong:
a,(-3x+2)\(^3\)
viet cac bieu thuc sau duoi dang tong:
a,(-3x+2)\(^3\)