nFeS2 = \(\dfrac{120000}{120}\) = 1000mol
2FeS2 + 2H2O + 7O2 \(^{to}\rightarrow\) 2FeSO4+ 2H2SO4
1000---------------------------------------->1000
=>mH2SO4(dung dịch) = 1000 . 1,84 = 1840 g
=>nH2SO4 = \(\dfrac{1840.98}{100.98}\) = 18,4 mol
=>mH2SO4 = 18,4 . 98 = 1803,2 g = 1,8032 kg
mà H = 80%
=> mH2SO4(thực tế) = 1,8032 . \(\dfrac{80}{100}\) = 1,44256 kg