Theo tính chất dãy tỉ số bằng nhau ta có :
\(\dfrac{MA}{AB}=\dfrac{MC}{BC}=\dfrac{MA+MC}{AB+BC}=\dfrac{AC}{AB+BC}=\dfrac{8}{6+10}=\dfrac{1}{2}\)
\(\left\{{}\begin{matrix}\dfrac{MA}{6}=\dfrac{1}{2}\Rightarrow MA=3cm\\\dfrac{MC}{10}=\dfrac{1}{2}\Rightarrow MC=5cm\end{matrix}\right.\)