\(\dfrac{a}{b}+\dfrac{-a}{b+1}=a\left(\dfrac{1}{b}-\dfrac{1}{b+1}\right)=\dfrac{a}{b\left(b+1\right)}\)
Đáp án: C
\(\dfrac{a}{b}+\dfrac{-a}{b+1}=a\left(\dfrac{1}{b}-\dfrac{1}{b+1}\right)=\dfrac{1}{b\left(b+1\right)}\)
=> Đáp án C
Ta có:\(\dfrac{a}{b}+\dfrac{-a}{b+1}=\dfrac{a}{b}-\dfrac{a}{b+1}=a\left(\dfrac{1}{b}-\dfrac{1}{b+1}\right)=a\dfrac{1}{b\left(b+1\right)}=\dfrac{a}{b\left(b+1\right)}\)
\(\)Đáp án đúng là A