Question

Tính:

\((\dfrac{1}{2}{x^4} - \dfrac{1}{4}{x^3} + x):( - \dfrac{1}{8}x)\).

Answer 1

\(\begin{array}{l}(\dfrac{1}{2}{x^4} - \dfrac{1}{4}{x^3} + x):( - \dfrac{1}{8}x) = \dfrac{1}{2}{x^4}:( - \dfrac{1}{8}x) - \dfrac{1}{4}{x^3}:( - \dfrac{1}{8}x) + x:( - \dfrac{1}{8}x)\\ = (\dfrac{1}{2}: - \dfrac{1}{8}).({x^4}:x) - (\dfrac{1}{4}: - \dfrac{1}{8}).({x^3}:x) + (1: - \dfrac{1}{8}).(x:x)\\ =  - 4.{x^{4 - 1}} - ( - 2).{x^{3 - 1}} + ( - 8).{x^{1 - 1}}\\ =  - 4{x^3} + 2{x^2} - 8\end{array}\)