Lời giải:
\(D=(\frac{1}{2}-1)(\frac{1}{3}-1)(\frac{1}{4}-1)...(\frac{1}{50}-1)=\frac{1-2}{2}.\frac{1-3}{3}.\frac{1-4}{4}...\frac{1-50}{50}\)
\(=\frac{-1}{2}.\frac{-2}{3}.\frac{-3}{4}....\frac{-49}{50}=-\frac{1.2.3.4...49}{2.3.4...50}=\frac{-1}{50}\)
Lời giải:
\(D=(\frac{1}{2}-1)(\frac{1}{3}-1)(\frac{1}{4}-1)...(\frac{1}{50}-1)=\frac{1-2}{2}.\frac{1-3}{3}.\frac{1-4}{4}...\frac{1-50}{50}\)
\(=\frac{-1}{2}.\frac{-2}{3}.\frac{-3}{4}....\frac{-49}{50}=-\frac{1.2.3.4...49}{2.3.4...50}=\frac{-1}{50}\)
C=2^2/1*3 *3^2/2*4*4^2/3*5...50*2/49*51
(1+1/2)×(1+1/3)×(1+1/4)×...×(1+1/100)
Bài 1: \(\frac{1}{6}\)+\(\frac{-5}{7}\): x = \(\frac{-7}{18}\)
Bài 2: Tìm tích
a)\(\left(\frac{1}{2}+1\right).\left(\frac{1}{3}+1\right).\left(\frac{1}{4}+1\right)...\left(\frac{1}{999}+1\right)\)
b)\(\left(\frac{1}{2}-1\right).\left(\frac{1}{3}-1\right).\left(\frac{1}{4}-1\right)...\left(\frac{1}{1000}-1\right)\)
c)\(\frac{3}{2^2}.\frac{8}{3^2}.\frac{15}{4^2}...\frac{99}{10^2}\)
1/1*2+1/3*4+1/5*6+.....+1/1317*1318
Nhanh giùm mình nha, mai thi rồi.
1/1×2+1/2×3+1/3×4+1/4×5+.....1/19×20
Tính:
(1-1/9). (1-2/9). (1-3/9)... (1-2005/9)Tính \(\frac{1^2}{2^2-1}.\frac{3^2}{4^2-1}.\frac{5^2}{6^2-1}...\frac{2011^2}{2012^2-1}\)
Chứng tỏ
\(1-\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{99}-\dfrac{1}{100}=\dfrac{1}{51}+\dfrac{1}{52}+...+\dfrac{1}{100}\)
Tính:
a,(1-1/5)x(1-2/5)x(1-3/5)x.....x(1-9/5)
b,1/2x2/3x3/4x4/5x.....x9/10