\(n_K=\dfrac{\dfrac{1}{2}\times10^{24}}{6\times10^{23}}=\dfrac{5}{6}\left(mol\right)\)
\(n_{O_2}=\dfrac{3,6\times10^{24}}{6\times10^{23}}=6\left(mol\right)\)
\(\dfrac{1}{2}\)=0,5 *1024 nguyên tử Kali
\(\Rightarrow n_K=\dfrac{0,5.10^{24}}{6,022.10^{23}}\approx0,083\left(mol\right)\)
3.6*1024 phân tử Ôxi(O2)
\(n_{O_2}=\dfrac{3,6.10^{24}}{6,022.10^{23}}\approx0,598\left(mol\right)\)