Question

Tính nhanh:

1 + 3 -5 - 7 + 9 + 11 - ... - 397 - 399

Answer 1

Đặt biểu thức là A

Ta có

\(A=\left(1+3-5-7\right)+\left(9+11-13-15\right)+.....+\left(393+395-397-399\right)\)

\(\Rightarrow A=\left[\left(1-5\right)+\left(3-7\right)\right]+......+\left[\left(393-397\right)+\left(395-399\right)\right]\)

\(\Rightarrow A=\left[\left(-4\right)+\left(-4\right)\right]+.....+\left[\left(-4\right)+\left(-4\right)\right]\)

\(\Rightarrow A=\left(-8\right)+.....+\left(-8\right)\)

\(\Rightarrow A=\left(-8\right).50\)

\(\Rightarrow A=-400\)