Đặt tử = A.Ta có:
\(A=0,75+\frac{3}{7}+\frac{3}{11}=\frac{3}{4}+\frac{3}{7}+\frac{3}{11}\)
\(=3\left(\frac{1}{4}+\frac{1}{7}+\frac{1}{11}\right)\)
Đặt mẫu = B.Ta có:
\(B=2\frac{1}{4}+\frac{9}{11}+\frac{9}{7}=\frac{9}{4}+\frac{9}{11}+\frac{9}{7}\)
\(=9\left(\frac{1}{4}+\frac{1}{11}+\frac{1}{7}\right)\)
Thay A và B vào ta đc: \(\frac{A}{B}=\frac{3\left(\frac{1}{4}+\frac{1}{7}+\frac{1}{11}\right)}{9\left(\frac{1}{4}+\frac{1}{11}+\frac{1}{7}\right)}=\frac{3}{9}=\frac{1}{3}\)