Giải:
\(PTK_{AlCl}=27+35,5=62,5\left(đvC\right)\)
\(PTK_{Na_2SO_4}=23.2+32+16.4=46+32+64=142\left(đvC\right)\)
\(PTK_{Cu\left(OH\right)_2}=64+2.16+2.1=64+32+2=98\left(đvC\right)\)
\(PTK_{CaSO_4}=40+32+16.4=40+32+64=136\left(đvC\right)\)
\(PTK_{H_2SO_4}=1.2+32+16.4=2+32+64=98\left(đvC\right)\)
\(PTK_{NaOH}=23+16+1=40\left(đvC\right)\)
\(PTK_{HNO}=1+14+16=31\left(đvC\right)\)
Chúc bạn học tốt!
AlCl=27+35,5=72,5(dvc)
Na2SO4 =(23.2)+32+(16.4)=
CaSO4=40+32+(16.4)=
H2SO4 = (1.2)+32+(16.4)=
NaOH=23+16+1=50 đvc
HNO=1+14+16=31(đvc)
Kết quả tự tính nha cậu!
AlCl=27+35,5
=62,5
\(Na_2SO_4\)=23.3+32+16.4
=165
\(Cu\left(OH_2\right)\)=64+16+1.2
=82
CaSO4=40+32+16.4
=136
H2SO4=1.2+32+16.4
=98
NaOH=23+16+1
=40
HNO=1+14+16
=31
Chúc bạn học tốt
