Question

Tính khối lượng của 0,2479 lít khí N2O

Answer 1

\(n_{N_2O}=\dfrac{V_{N_2O}}{24,79}=\dfrac{0,2479}{24,79}=0,01\left(mol\right)\) 
\(m_{N_2O}=n_{N_2O} . M_{N_2O}=0,01 . \left(14 . 2+16\right)=0,01 . 44=0,44\left(g\right)\)

Answer 2

\(n_{N_2O\left(dkc\right)}=\dfrac{V}{24,79}=\dfrac{0,2479}{24,79}=0,01\left(mol\right)\\ m_{N_2O}=n\cdot M=0,01\cdot\left(14\cdot2+16\right)=0,44\left(g\right)\)

Answer 3

n_N2O = \(\dfrac{0,2479}{22,4}\)

n_N2O = 0,01 ( mol )

m_N2O= M_N2O.n_N2O

m_N2O = 0,01 . 44 = 0,44 ( g/mol )

Answer 4

\(n_{N_2O}=\dfrac{0,2479}{24,79}=0,01\left(mol\right)\\ m_{N_2O}=0,01.44=0,44\left(g\right)\)