\(y=2-2.\left(2sinx.cosx\right)=2-2sin2x\)
Do \(-1\le sin2x\le1\Rightarrow0\le y\le4\)
\(y_{min}=0\) khi \(sin2x=1\Rightarrow x=\dfrac{\pi}{4}+k\pi\)
\(y_{max}=4\) khi \(sin2x=-1\Rightarrow x=-\dfrac{\pi}{4}+k\pi\)
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