Ta có:
\(a\perp AB\left(gt\right)\)
\(b\perp AB\left(gt\right)\)
\(\Rightarrow a\) // \(b\)
Ta có:
\(\widehat{DCa}+\widehat{ACD}=180^0\) (kề bù)
\(\Rightarrow\widehat{DCa}=180^0-\widehat{ACD}\)
\(=180^0-120^0\)
\(=60^0\)
Do \(a\) // \(b\)
\(\Rightarrow\widehat{BDC}=\widehat{ACD}=60^0\) (so le trong)