Cho hình vẽ. BIết \(a\)//\(b\), \(\widehat{A_1}-\widehat{C_1}=40^0\). Tính \(\widehat{A_2}\), \(\widehat{C_2}\).
- \(\widehat{A_2}=80^0\), \(\widehat{C_2}=110^0\).
- \(\widehat{A_2}=110^0\), \(\widehat{C_2}=70^0\).
- \(\widehat{A_2}=70^0\), \(\widehat{C_2}=110^0\).
- \(\widehat{A_2}=70^0\), \(\widehat{C_2}=70^0\).