\(3x^2-2x-8=0\)
\(\Leftrightarrow3x^2-6x+4x-8=0\)
=>(x-2)(3x+4)=0
=>x=2 hoặc x=-4/3
\(P\left(2\right)=6\cdot4-4\cdot2+9=25\)
\(P\left(-\dfrac{4}{3}\right)=6\cdot\dfrac{16}{9}-4\cdot\dfrac{-4}{3}+9\)
\(=\dfrac{32}{3}+\dfrac{16}{3}+9=\dfrac{48}{3}+9=25\)