Question

Tính giá trị của các biểu thức sau :

\(A=27+46+79+34+53\)

\(B=-377-\left(98-277\right)\)

\(C=-1,7.2,3+1,7.\left(-3,7\right)-1,7.3-0,17:0,1\)

\(D=2\dfrac{3}{4}.\left(-0,4\right)-1\dfrac{3}{5}.2,75+\left(-1,2\right):\dfrac{4}{11}\)

\(E=\dfrac{\left(2^3.5.7\right).\left(5^2.7^3\right)}{\left(2.5.7^2\right)^2}\)

 

Answer 1

Answer 2

A = 27 + 46 + 79 + 34 + 53 = 239

B = - 377 - (98 - 277)

= - 377 - 98 + 277

= -198

C = - 1,7× 2,3 + 1,7.× (- 3,7) - 1,7×3 - 0,17:0,1

= 1,7. (-2,3 – 3,7 – 3 – 1)

= 1,7 . (-10)

= -17.

D = $2\frac{3}{4}.\left(-0,4\right)-1\frac{3}{5}.2,75+\left(-1,2\right):\frac{4}{11}$

$=\frac{11}{4}.\frac{-4}{10}-\frac{8}{5}.\frac{11}{4}+\frac{-6}{5}.\frac{11}{4}$

$=\frac{11}{4}.\left(\frac{-4}{10}-\frac{8}{5}+\frac{-6}{5}\right)$

$=\frac{11}{4}.\frac{-2-8-6}{5}$

$=\frac{11}{4}.\frac{-16}{5}$

$=\frac{}{}$

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Answer 3

a=239

b=-198

c=-17

d=-44/5

e=10

Answer 4

Answer 5

A= (27 + 53) + (46 + 34) + 79

A= 80 + 80 + 79

A = 239

Vay A = 239