Question

Tính bằng cách hợp lí (nếu có thể)

( \(\frac{-1}{4}\) + \(\frac{7}{33}\) - \(\frac{5}{3}\)) - (-\(\frac{15}{12}\)  + \(\frac{6}{11}\) - \(\frac{48}{49}\))?

Answer 1

\(=\left(-\frac{1}{4}-\frac{5}{3}\right)+\frac{7}{33}+\frac{15}{12}-\frac{6}{11}+\frac{48}{49}\)

\(=-\frac{23}{12}+\frac{7}{33}+\frac{15}{12}-\frac{6}{11}+\frac{48}{49}\)

\(=\left(-\frac{23}{12}+\frac{15}{12}\right)+\left(\frac{7}{33}-\frac{6}{11}\right)+\frac{48}{49}\)

\(=-\frac{2}{3}-\frac{1}{3}+\frac{48}{49}\)

\(=-\frac{3}{3}+1-\frac{1}{49}\)

\(=-1+1-\frac{1}{49}\)

\(=-\frac{1}{49}\)

Answer 2

C1: 

= \(-\frac{1}{4}+\frac{7}{33}-\frac{5}{3}+\frac{15}{12}-\frac{6}{11}+\frac{48}{49}=\left(-\frac{1}{4}+\frac{15}{12}\right)+\left(\frac{7}{33}-\frac{5}{3}-\frac{6}{11}\right)+\frac{48}{49}\)

=\(1-2+\frac{48}{49}=\frac{48}{49}-1=-\frac{1}{49}\)