Question

Tính bằng cách hợp lí

B =\(\frac{1}{11}\cdot2\frac{30}{31}+3\frac{1}{55}\cdot\frac{1}{31}-\frac{3}{11}+\frac{6}{55\cdot31}\)

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Answer 1

Lời giải:
\(B=\frac{1}{11}.2\frac{30}{31}+3\frac{1}{55}.\frac{1}{31}-\frac{3}{11}+\frac{6}{55.31}\)

\(=\frac{1}{11}(2+\frac{30}{31})+(3+\frac{1}{55}).\frac{1}{31}-\frac{3}{11}+\frac{6}{55.31}\)

\(=\frac{2}{11}+\frac{30}{11.31}+\frac{3}{31}+\frac{1}{55.31}-\frac{3}{11}+\frac{6}{55.31}\)

\(=(\frac{2}{11}-\frac{3}{11})+\frac{31-1}{11.31}+\frac{3}{31}+(\frac{1}{55.31}-\frac{6}{55.31})\)

\(=\frac{-1}{11}+\frac{1}{11}-\frac{1}{11.31}+\frac{3}{31}-\frac{1}{11.31}\)

\(=\frac{-2}{11.31}+\frac{3}{31}=\frac{-2}{11.31}+\frac{33}{11.31}=\frac{33-2}{11.31}=\frac{31}{11.31}=\frac{1}{11}\)