Question

tìm x,y

5/x - y/3 = 1/6

Answer 1

\(\frac{5}{x}-\frac{y}{3}=\frac{1}{6}\)

\(\Rightarrow\frac{5}{x}-\frac{2y}{6}=\frac{1}{6}\)

\(\Rightarrow\frac{5}{x}=\frac{1}{6}-\frac{2y}{6}\)

\(\Rightarrow\frac{5}{x}=1-\frac{2y}{6}\)

\(\Rightarrow5.6=x\left(1+2y\right)\)

\(\Rightarrow30=x\left(1+2y\right)\)

\(\Rightarrow2y=2k\Rightarrow1+2y=2k+1\)

\(\Rightarrow1+2y=1;3;5;15;-1;-3;-5;-30\)

\(\Rightarrow x\in\left\{30;10;6;2;-30;-10;-6;-2\right\}\)

 

Answer 2

\(\frac{5}{x}-\frac{y}{3}=\frac{1}{6}\)

\(\Rightarrow\frac{5}{x}-\frac{2y}{6}=\frac{1}{6}\)

\(\Rightarrow\frac{5}{x}=\frac{1}{6}-\frac{2y}{6}\)

\(\Rightarrow\frac{5}{x}=\frac{1-2y}{6}\)

\(\Rightarrow5.6\Rightarrow=x\left(1-2y\right)\)

\(\Rightarrow30=x\left(1-2y\right)\)

\(\Rightarrow x\in UC\left(30\right)\)

\(\Rightarrow x\in\left\{\pm1;\pm2;\pm3;\pm5;\pm6;\pm10;\pm15;\pm30\right\}\)

lập bẳng xét từng trường hợp x để tìm y

Answer 3

Ta có 5/x - y/3 = 1/6

 <=> 1/6 + y/3 = 5/x

<=> 1 + 2y/6 = 5/x

=>x và 1 + 2y là Ư(30)

mà 1 + 2y là ước lẻ của 30 => 1+2y $e${1,3,5,15}

Ta có :

1+2y	1	3	5	15
x	30	10	6	2

=>

2y	0	2	4	14
x	30	10	6	2

=>

y	0	1	2	7
x	30	10	6	2