a) x.y+3.x=66
x.(y+3)=66
=> (y+3)∈Ư(66) | 3<y+3<66
=> y+3 ∈ {3,6,11,22,33}
y | 6 | 11 | 22 | 33 | ||
x | 22 | ∅ | ∅ | ∅ |
b) x+y=288 và ƯCLN(x,y)=24
=>x⋮24 , y⋮24
=>y+x⋮24
Ta có : x=24.q , y=24.k
24q+24k=x+y
hay 24q+24k=288
24.(q+k)=288
q+k=288/24
q+k=12=1+11=5+7
q | 11 | 1 | 7 | 5 |
k | 1 | 11 | 5 | 7 |
a | 264 | 24 | 168 | 120 |
b | 24 | 264 | 120 | 168 |