\(\frac{x+1}{2}=\frac{8}{x+1}\)
\(\Rightarrow\left(x+1\right)^2=16\)
\(\Rightarrow x+1=4\) hoặc \(x+1=-4\)
*\(x+1=4\Rightarrow x=3\)
*\(x+1=-4\Rightarrow x=-5\)
Vậy \(\text{x = 3; x = -5}\)
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