Ôn tập toán 7
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Tìm x: \(x-\frac{\frac{x}{2}-\frac{x}{3}}{4}-\frac{x}{6}=\frac{2\left(1+x\right)}{3}-\frac{\frac{x}{3}+\frac{1-x^7}{4}}{2}\)
Tìm x: \(\frac{3\frac{1}{2}x-4}{6}+\frac{2+\frac{1}{4}x}{3}=1\frac{1}{4}x\left(x-1\right)-\frac{7-\frac{3}{4}x}{3}\)
Giúp mk vs đg cần gấp nha cảm ơn mấy bạn nhiều lắm !!!left(frac{1}{2}right)^5.xleft(frac{1}{2}right)^7left(frac{3}{7}right)^2.xleft(frac{9}{21}right)^2Bài tìm x biết :2x23x347x77(-3)x(-3)5(-5)x(-5)42x42x82x163x+1325x-156x+461052x-7511(-2)4x+264left(frac{1}{2}right)^xleft(frac{1}{2}right)^5left(frac{5}{6}right)^{2x}left(frac{5}{6}right)^5left(frac{3}{4}right)^{2x-1}left(frac{3}{4}right)^{5x-4}left(-frac{1}{10}right)^xfrac{1}{100}left(-frac{3}{2}right)^xfrac{9}{4}left(-frac{3}{5}right)^{2x}frac{9}...
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Giúp mk vs đg cần gấp nha cảm ơn mấy bạn nhiều lắm !!!
\(\left(\frac{1}{2}\right)^5.x=\left(\frac{1}{2}\right)^7\)
\(\left(\frac{3}{7}\right)^2.x=\left(\frac{9}{21}\right)^2\)
Bài tìm x biết :
2x=2
3x=34
7x=77
(-3)x=(-3)5
(-5)x=(-5)4
2x=4
2x=8
2x=16
3x+1=32
5x-1=5
6x+4=610
52x-7=511
(-2)4x+2=64
\(\left(\frac{1}{2}\right)^x=\left(\frac{1}{2}\right)^5\)
\(\left(\frac{5}{6}\right)^{2x}=\left(\frac{5}{6}\right)^5\)
\(\left(\frac{3}{4}\right)^{2x-1}=\left(\frac{3}{4}\right)^{5x-4}\)
\(\left(-\frac{1}{10}\right)^x=\frac{1}{100}\)
\(\left(-\frac{3}{2}\right)^x=\frac{9}{4}\)
\(\left(-\frac{3}{5}\right)^{2x}=\frac{9}{25}\)
\(\left(-\frac{2}{3}\right)^x=-\frac{8}{27}\)
Tìm x in Za,frac{1}{2}-left(frac{1}{3}+frac{1}{4}right) x frac{1}{48}-left(frac{1}{16}-frac{1}{6}right)b, frac{3}{4}-frac{5}{6}lefrac{x}{12} 1-left(frac{2}{3}-frac{1}{3}right)c, x:left(frac{1}{2}right)^2frac{-1}{2}d,left(x^4right)^2frac{x^{12}}{x^5}left(xne0right)e,frac{3^2.3^8}{27^3}3^xf,2^{x-1}left(16right)^5
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Tìm x \(\in\) Z
a,\(\frac{1}{2}-\left(\frac{1}{3}+\frac{1}{4}\right)< x< \frac{1}{48}-\left(\frac{1}{16}-\frac{1}{6}\right)\)
b, \(\frac{3}{4}-\frac{5}{6}\le\frac{x}{12}< 1-\left(\frac{2}{3}-\frac{1}{3}\right)\)
c, \(x:\left(\frac{1}{2}\right)^2=\frac{-1}{2}\)
d,\(\left(x^4\right)^2=\frac{x^{12}}{x^5}\left(x\ne0\right)\)
e,\(\frac{3^2.3^8}{27^3}=3^x\)
f,\(2^{x-1}=\left(16\right)^5\)
tìm x, x\(\in\) Q:
\(\frac{\left(x+\frac{3}{4}\right).\frac{7}{2}-\frac{1}{6}}{-\left(\frac{4}{5}+\frac{1}{3}\right).\frac{1}{2}+1}=2\frac{33}{52}\)
\(\frac{\left(5-\frac{2}{7}\right).\frac{7}{9}:\frac{3}{5}}{\left(3x-\frac{5}{6}\right):\frac{1}{7}}=5\frac{5}{21}\)
\(a,\left|x-\frac{2}{5}\right|=0,5-\left(-\frac{1}{2}\right)\)
\(b,\frac{3}{2}\left|\frac{1}{4}-x\right|=\frac{5}{6}-1\)
\(c,\frac{4}{3}-\frac{5}{3}\left|x-\frac{1}{3}\right|=-\frac{1}{6}\div\frac{2}{3}\)
1. Tính hợp lí :
a) \(\frac{3}{4}-0,25-\left[\frac{7}{3}+\left(\frac{-9}{2}\right)\right]-\frac{5}{6}\)
b) 7 + \(\left(\frac{7}{12}-\frac{1}{2}+3\right)-\left(\frac{1}{12}+5\right)\)
2. Tìm các sô nguyên x biết:
\(\frac{3}{4}-\frac{5}{6}\le\frac{x}{12}< 1-\left(\frac{2}{3}-\frac{1}{4}\right)\)
Tìm x : \(\frac{\left(x-3\right)^2}{2}-1\frac{1}{3}\left(x+2\right)^2-\frac{5}{4}\left(x-1\right)\left(x+1\right)=1\frac{1}{2}x\left(x-2\right)-x-4\)
Tìm x \(\in\) Z biết:
a) \(\frac{1}{2}-\left(\frac{1}{3}+\frac{1}{4}\right)< x< \frac{1}{48}-\left(\frac{1}{16}-\frac{1}{6}\right)\) b) \(4\frac{5}{9}:2\frac{5}{18}-7< x< \left(3\frac{1}{5}:3,2+4,5.1\frac{31}{45}\right):\left(-21\frac{2}{3}\right)\)