a, \(x=\left(-1\right)+\left(-99\right)\)
\(x=-100\)
Vậy \(x=-100\)
b, \(x=\left(-105\right)+\left(-15\right)\)
\(x=-120\)
Vậy \(x=-120\)
a) x = 1+99
x = 100
b) x = 105 + 15
x = 120
a) (-1) + (-99) = -(1 + 99) = -100. Vậy x = -100
b) (-105) + (-15) = -(105 + 15) = -120. Vậy x = -120
a, (-1) +(-99) = -(1+99) = -100.Vậy x = -100
b,(-105) + (-15) = -(105 + 15) = -120.Vậy x = -120
a, (-1) +(-99) = -(1+99) = -100.Vậy x = -100
b,(-105) + (-15) = -(105 + 15) = -120.Vậy x = -120