Question

Tìm x,biết :

\(\dfrac{1}{6} + \dfrac{-5}{7} : x = \dfrac{-7}{8}\)

Answer 1

Ta có :

\(\dfrac{1}{6}+\dfrac{-5}{7}:x=\dfrac{-7}{8}\)

\(\dfrac{-5}{7}:x=\dfrac{-7}{8}-\dfrac{1}{6}\)

\(\dfrac{-5}{7}:x=\dfrac{-25}{24}\)

\(x=\dfrac{-5}{7}:\dfrac{-25}{24}\)

\(x=\dfrac{24}{35}\)

Vậy \(x=\dfrac{24}{35}\) là giá trị cần tìm

~ Học tốt ~

Answer 2

\(\dfrac{1}{6}+\dfrac{-5}{7}\)\(:\) \(x=\)\(\dfrac{-7}{8}\)

\(\dfrac{-5}{7}:\) \(x=\dfrac{-7}{8}-\dfrac{1}{6}\)

\(\dfrac{-5}{7}\) \(:\) \(x=\)\(\dfrac{-25}{24}\)

\(x=\dfrac{-5}{7}:\dfrac{-25}{24}\)

\(x=\dfrac{24}{35}\)