4)\(=>x=\dfrac{5}{12}:\left(\dfrac{2}{3}-\dfrac{1}{2}\right)=\dfrac{5}{12}:\dfrac{1}{6}=\dfrac{5}{2}\)
5)\(=>\dfrac{9}{4}\cdot\left(x-\dfrac{22}{3}\right)=\dfrac{3}{2}\)
\(=>x=\left(\dfrac{3}{2}:\dfrac{9}{4}\right)+\dfrac{22}{3}=\dfrac{2}{3}+\dfrac{22}{3}=\dfrac{24}{3}=8\)