=>1/2x+2/3x-2/3=1/3
=>7/6x=1
hay x=6/7
\(\dfrac{x}{2}+\dfrac{2x}{3}-\dfrac{2}{3}=\dfrac{1}{3}\Leftrightarrow\dfrac{3x+4x}{6}=1\Rightarrow7x=6\Leftrightarrow x=\dfrac{6}{7}\)
=>1/2x+2/3x-2/3=1/3
=>7/6x=1
hay x=6/7
\(\dfrac{x}{2}+\dfrac{2x}{3}-\dfrac{2}{3}=\dfrac{1}{3}\Leftrightarrow\dfrac{3x+4x}{6}=1\Rightarrow7x=6\Leftrightarrow x=\dfrac{6}{7}\)
\(\dfrac{x+2}{7}\)=\(\dfrac{-36}{28}\)
tìm x:
2 tìm x
a) x+25=40
b) 198-(x+4)=120
c) (2x-7).3=125
d) x +16⋮x+1
Tìm X
Tìm X
Tìm X
bài 45: Tìm x, biết:
a) x=\(\dfrac{-1}{2}+\dfrac{3}{4}\); b) \(\dfrac{x}{5}=\dfrac{5}{6}+\dfrac{-19}{30}\)
tìm x, biết:
e) \(\dfrac{2}{7-x}\)=\(\dfrac{18}{45}\) f)\(\dfrac{2x+3}{3}\)=\(\dfrac{50}{15}\) g)\(2\dfrac{x}{7}\)=\(\dfrac{75}{35}\) h)\(2\dfrac{3}{x}\)=\(\dfrac{13}{x}\)(x khác 0)
Tìm \(x\), biết :
a) \(x=\dfrac{1}{4}+\dfrac{2}{13}\)
b) \(\dfrac{x}{3}=\dfrac{2}{3}+\dfrac{-1}{7}\)
Tìm \(x\) biết :
a) \(x=\dfrac{-1}{2}+\dfrac{3}{4}\)
b) \(\dfrac{x}{5}=\dfrac{5}{6}+\dfrac{-19}{30}\)